7. a) Classify the following bonds as ionic, polar covalent, or nonpolar qualita
ID: 504920 • Letter: 7
Question
7. a) Classify the following bonds as ionic, polar covalent, or nonpolar qualitatively based solely on each element's position on the periodic table. S-S Na-N O-I S-Cl Cu-Cl
b) Classify the bonds (ionic, polar covalent, nonpolar) formed between each pair of elements based on electronegativity values in the following table: Element 1.) Sc 2.) Be 3.) H 4.) P 5.) S 6.) I 7.) Br 8.) Cl 9) O 10) F
Electronegativity 1) 1.3 2) 1.5 3) 2.1 4) 2.1 5) 2.5 6) 2.5 7) 2.8 8) 3.0 9) 3.5 10) 4.0
H-Br H-P S-O Be-F Be-Cl
Explanation / Answer
Guide line for ionic, covalent or nonpolar bonds:
Electronegativity difference between bonded atoms = 0 then its nonpolar.
= more than 0 and less than 1.7 are polar covalent.
= greater than 1.7 are ionic.
7. a) S-S (difference between two atoms would be zero due to same atom hence, nonpolar qualitatively)
Na-N (difference between two atoms would be more due to more difference in there periodic position hence, ionic bond)
O-I (difference between two atoms would be less due to less difference in their periodic position hence, polar covalent bond)
S-Cl (difference between two atoms would be less due to less difference in their periodic position hence, polar covalent bond)
Cu-Cl (difference between two atoms would be less due to less difference in there periodic position hence, polar covalent bond)
b) H-Br (difference of electronegativity between two atoms = 2.8-2.1 = 0.7 hence, polar covalent bond)
H-P (difference of electronegativity between two atoms = 2.1-2.1 = 0.0 hence, non polar bond)
S-O (difference of electronegativity between two atoms = 3.5-2.5 = 1.0 hence, polar covalent bond)
Be-F (difference of electronegativity between two atoms = 4.0-1.5 = 2.5 hence, ionic bond)
Be-Cl (difference of electronegativity between two atoms = 3.0-2.1 = 0.9 hence, polar covalent bond)
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.