A gas mixture contains 10.0 g He, 10.0 g Ne, and 10.0 g Ar. If the total pressur

Question

A gas mixture contains 10.0 g He, 10.0 g Ne, and 10.0 g Ar. If the total pressure of the mixture is 600.0 mmHg. determine the partial pressure of Ne in the sample. A) 461.5 mmHg B) 138.5 mmHg C) 92.31 mmHg D) 46.15 mmHg 6. 6. A gas mixture contains 10.0 g He, 10.0 g Ne, and 10.0 g Ar. If the temperature of the sample is 300.0 K, which component has the highest average kinetic energy? A) He B)Ne C) Ar D) All components have the same average kinetic energy 7. A gas mixture contains 10.0 g He, 10.0 g Ne, and 10.0 g Ar. If the temperature of the sample is 300.0 K, which component will effuse (leak out of a small hole) fastest? A) He B) Ne C) Ar D) All components will effuse at the same rate

Explanation / Answer

5. Mole of He =10g/4g=2.5 mole

Mole of Ne = 10g/20.18g =0.50 mole

Mole of Ar = 10g/39.95g = 0.25 mole

Total no of moles = 3.25 mole

Mole fraction of He = 2.5/3.25 = 0.7692

Mole fraction of Ne = 0.50/3.25 = 0.1538

Mole fraction of At = 0.25/3.25 = 0.0769

Partial pressure of Ne = 600 ×0.1538 = 92.28mmHg

Therefore , The answer is C) 92.31

6.The answer is A) He because lower molar mass gas will have higher kinetic energy

7.The answer is A) He because lower the molar mass and higher will be speed and effusion will be fast.

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