Given the following 3 beakers, where only osmosis can occur, determine if the \'
ID: 495564 • Letter: G
Question
Given the following 3 beakers, where only osmosis can occur, determine if the 'cell' in will shrink, expand or stay the same. Calculate the following for the ingredients in an Excedrin tablet. You must show your work. Molecular weight of caffeine, C_8H_9NO_2 (151 g/mol) Number of grams of aspirin in 0, 014 moles C_9H_8O_4 (180 g/mol) The recommended dose of acetaminophen is 650 to 100 mg every 4 to 6 hours as needed, not to exceed 4000 mg in 24 hours. Given that an Excedrin tablet contains 8.36 times 10^20 molecules of acetaminophen. How many tablets would provide the upper limit of too much Excedrin in 24 hours? Given the following correctly BALANCED reaction: C_11H_24 + 10O_2 rightarrow 11CO_2 + 12 H_o + 12H_2O Delta H = -1778 Kcals/mol How grams of carbon dioxide are produced from 600 grams of C_11H_24 (undecane) How many moles of undecane will melt 100 grams of water (heat of fusion = 80cal/g)? When 1560 of grams of grams of C_11H_24 (undecane) are mixed with 200 moles of oxygen, which substance is the limiting reagent? How many grams of these excess reagents remain after complete reaction?Explanation / Answer
Solution:
1. The beaker state is nased on the water and solute % of the two chamber one in beaker and other in rounded figure, when both water and solute level are same in both chamber the size remains same unless it starts to shrink based on this beaker 1 = expands, beaker 2 = shrinks beaker 3 = remains same.
2. Molar mass of caffeine C8H10N4O2 = (8*12.011)+(10*1.008)+(4*14.007)+(2*15.999)=194.191 g/mol
3. No. of moles in acetaminophen = (0.25 gm) / (151 g/mol) = 0.00166 moles
4. Aspiring mass in gm = 0.014 moles*180 g/mol = 2.52 gm
5. Excedrin moles = (8.36*1020)/(6.022*1023)=0.001388 moles
Mass of Excedrin = 0.001388 moles * 525.518 (g/mol) = 0.7294 g = 729.41 mg
for 4000 mg no. of tablets required = (4000 mg) / (729.41 mg) = 5.48 = 6 tablets required approx.
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