Given the element values. Calculate the current ixix using the branch current me
ID: 3161510 • Letter: G
Question
Given the element values. Calculate the current ixix using the branch current method (BCM) a function of i1i1. Prove your answers are correct by multiplying your solution for ixix by R1R1and showing that this product is vxvx.
Here, v1=10Vv1=10V, v2=11Vv2=11V, i1i1 is a variable (AA), i2=18Ai2=18A, i3=20Ai3=20A, R1=5R1=5, R2=9
Explanation / Answer
Here, Using BCM
for the current in resistance R2 (Iy)
iy - ix + i1 + i2 - i3 = 0
>> iy = ix + i3 - i1 - i2
Using KVL in the loop with V1 and V2
V1 + V2 = iy * R2 + ix * R1
10 + 11 = 9 * (ix + i3 - i1 - i2) + ix * 5
10 + 11 = 9 * (ix + 20 - i1 - 18) + ix * 5
3 = 14 * ix - 9 * i1
ix = (3 + 9 * i1)/14
the formula for ix is (3 + 9 * i1)/14
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