The rate of a certain reaction is given by the following rate law: rate = k[N_2]

Question

The rate of a certain reaction is given by the following rate law: rate = k[N_2]^3[O_3] Use this information to answer the questions below. What is the reaction order in N_2? What is the reaction order in O_3? What is overall reaction order? At a certain concentration of N_2 and O_3, the initial rate of reaction is 0.560 M/s. What would the initial rate of the reaction be if the concentration of N_2 were doubled? Round your answer to 3 significant digits. The rate of the reaction is measured to be 4.0 times 10^3 M/s when [N_2] = 0.044 M and [O_3] = 1.4 M. Calculate the value of the rate constant. Round your answer to 2 significant digits.

Explanation / Answer

from the rate law

order with respect to N2 = 3

order with respect to O3 = 1

overall order = 3 + 1 = 4

if we double the concentration of reactants N2 rate will increased by 27 times (33)

so rate = 0.56 x 27 = 15.12 M/s

K = rate / [N2]3 [O3]

K = (0.004) / (0.044)3 (1.4) = 0.004 / 0.000119

K = 33.6 M-3 s-1

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