The rate constant of a chemical reaction increased from 0.100 s %u2212 1 to 3.20

Question

The rate constant of a chemical reaction increased from 0.100 s%u22121 to 3.20s%u22121  upon raising the temperature from 25.0 %u2218C to 55.0%u2218C . Part A Calculate the value of (1T2%u22121T1) where T1 is the initial temperature and T2 is the final temperature. Express your answer numerically.

Part B Calculate the value of ln(k2k1) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A. Express your answer numerically The rate constant of a chemical reaction increased from 0.100 s%u22121 to 3.20s%u22121  upon raising the temperature from 25.0 %u2218C to 55.0%u2218C . The rate constant of a chemical reaction increased from 0.100 s%u22121 to 3.20s%u22121  upon raising the temperature from 25.0 %u2218C to 55.0%u2218C . Part A Calculate the value of (1T2%u22121T1) where T1 is the initial temperature and T2 is the final temperature. Express your answer numerically.

Part B Calculate the value of ln(k2k1) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A. Express your answer numerically Part A Calculate the value of (1T2%u22121T1) where T1 is the initial temperature and T2 is the final temperature. Express your answer numerically.

Part B Calculate the value of ln(k2k1) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A. Express your answer numerically Part B Calculate the value of ln(k2k1) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A. Express your answer numerically

Explanation / Answer

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a) -3.069*10^(-4)

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