SUMMARY OF DATA: Molarity of S203 o olhoM Part II: Titration of water layer Part
ID: 481289 • Letter: S
Question
SUMMARY OF DATA: Molarity of S203 o olhoM Part II: Titration of water layer Part III: Reaction of mineral oil layer volume of mineral oil min. volume of layer mL S2032 ml for Volume of Volume of water layer S2032 mL mL, Colour changes Run 1 Run 2 CALCULATIONS figures, or All calculations must include units and have the correct number of significant mark(s) will be No marks will be given if supporting work is not shown. oil layer from deducted. the mineral 1. Use your value of the minimum volume of S203 to change blue to colourless, and Equation (11) to calculate [I20organic)]at equilibrium. 2marks) Answer 2. Use your answer from Question 1 to calculate [I20aq at equilibrium in the aqueous layer. (1 mark) Answer inna on the next page)Explanation / Answer
The titration of I2 released by S2O32- is given by the equation-
2S2O32-(aq)+I2(aq)---->S4O62-(aq)+2I-(aq)
1)[I2(organic )]=M1
Volume of (organic layer)=V1=9.94ml
[S2O32-]=0.0150M=M2
V2=volume of S2O32-=4.5ml
As M1*V1/M2*V2=moles of I2/moles of S2O32-=1/2
2M1*V1=M2*V2
M1=M2*V2/2V1=0.0150M*4.5ml/2*9.94ml=0.0034M
M1=[I2(organic)]=0.0034M
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