An electron accelerated from rest through a voltage of 420 V enters a region of

Question

An electron accelerated from rest through a voltage of 420V enters a region of constant magnetic field.

Part A If the electron follows a circular path with a radius of 18cm , what is the magnitude of the magnetic field? An electron accelerated from rest through a voltage of 420V enters a region of constant magnetic field.

An electron accelerated from rest through a voltage of 420V enters a region of constant magnetic field.

An electron accelerated from rest through a voltage of 420V enters a region of constant magnetic field.

Part A If the electron follows a circular path with a radius of 18cm , what is the magnitude of the magnetic field?

Explanation / Answer

since the radius of the motion is given we have from balancing the forces on the electron B*e*v = m*v^2/r

here B = strength of magnetic field, e = chanrge on the electron, v = velocity of the electron

=> now given the voltage is 420V => the velocity is given from 1/2*m*v^2 = e*420

=> .5*9.1*10^-31 * v^2 = 1.67*10^-19 *420

=> v = 12415861 m/s

=> B = 3.7586*10^-4

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