For a mixture of ethane 60 %, acetylene 20%, and benzene 20% total mass of 250 k

Question

For a mixture of ethane 60 %, acetylene 20%, and benzene 20% total mass of 250 kg is loaded

into a reactor obeying the Carnot cycle, we want to know which produces more work when

reacted with 25% fuel, 60% O2, 15% CO2 for 30 cycles. Calculate the amount of each fuel in the

mixture; perform mass balance to obtain the amount of fuel that is actually reacting in the mixture

if the reaction runs with 40% efficiency

Running only ETHANE on an ideal engine, the first process is performed at standard pressure

30 C, in the heating and compression process the chambers have a pressure of 35atm and a

temperature of 575C, calculate the work performed in 30 cycles. Draw the PV diagram for the

engine and label the state variable on their corresponding positions. Like (process 1 -> 2 ect and

describe what kind of process it is).How efficient is this engine?

Explanation / Answer

Total fuel percentage: 60% ethane, 20% acetylene, 20 % benzene . Total mass = 250ethanle 150 KG, Acetylene= benzene = 50 KgNow total fuel is 25%, which is 250 Kg. it means total weight of fuel+O2+CO2 = 1000 Kg , where 600Kg is O2 and 150 Kg is CO2 C2H6 + 7/2 O2 ---> 2CO2 + 3 H2OC2H2 + 5/2 O2 ---> 2CO2 + H2OC6H6 + 15/2 O2 --> 6CO2 + 3H2O

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