For a human body falling though air in a spread- eagle position, the numerical v

Question

For a human body falling though air in a spread- eagle position, the numerical value of the constant D is about D = 0.250kg/m. Part A What value of D is required to make vt = 42.3m/s the terminal velocity of a skydiver of mass 77.0kg Express your answer using two significant figures. kg/m Part B If the sky diver's daughter, whose mass is 43.0kg, is falling through the air and has the same D (D = 0.25 kg/m) as her father, what is the daughter's terminal speed? Express your answer using two significant figures. m/s

Explanation / Answer

The value of D can be calculated as follows:

          D = mg/v2 = 77*9.8 / (42.3)2 = 0.42 kg/m

The terminal speed is,

          v = [mg/D]1/2 = [43*9.8/0.25]1/2 = 41.05 m/s

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