For Assembly Language x86: I have the following code: It currently outputs: Ente

Question

For Assembly Language x86:

I have the following code:

It currently outputs:

Enter a number
4
Enter a number
3
7 ;// after adding 4+3
+7 ;// help

My question is how can I perform subtraction between my two entered integers so the result will be 1 instead of +7?

.data prompt BYTE " Enter a number ", 0dh, 0ah, 0 val DWORD? val2 DWORD? .code main proc mov edx, OFFSET prompt; call Writestring call ReadInt mov val, eax call Writestring call ReadInt add eax, val mov val2, eax call WriteDec call Crlf sub val, eax call WriteInt call Crlf invoke ExitProcess,0 main endp end main

Explanation / Answer

WriteInt prints integer value with sign while WriteDec does not print sign of interger.

so editing WriteDec to WriteInt prints +7 instead of 7.

for printing subtracted value of two numbers,

.data

prompt BYTE "Enter a number", 0dh, 0ah, 0

val DWORD ?

val2 DWORD ?

.doc

main proc

mov edx, OFFSET prompt;

call WriteString

call ReadInt

mov val, eax

call WriteString

call ReadInt

sub val, eax

call WriteDec

call Clrf

invoke ExitProcess,0

main endp

end main

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