For 22. In part (c), only show that the geometric random variable is memoryless;
ID: 3061030 • Letter: F
Question
For 22. In part (c), only show that the geometric random variable is memoryless; showing that a distribution on the positive integers is necessarily memoryless is harder.
22. Let X be a geometric random variable with parameter p, and n and m be nonnegative integers.
(a) For what values of n is P (X = n) maximum?
(b) What is the probability that X is even?
(c) Show that the geometric is the only distribution on the positive integers with the memoryless property: P (X > n + m | X > m) = P (X > n)
I just need the first question answered. Thanks.
Explanation / Answer
Question 22
(a) Here P(X = n) = (1-p)n-1p
so for maximum value of probability dP/dn = 0
dP/dn = (n-1) (1-p)n-2
so at n = 1 we have the maximum value of P( x = n) which would be equal to p
(b) Here Pr(x = Even) = P(x = 2) + P(X = 4) + ....
= (1-p)p + (1-p)3p+ ...
= (1-p)p [1 + (1-p)2 + ...]
= (1-p)p [1/ (1 -(1-p)2)]
= p(1-p) * 1/ [1 - (1 + p2-2p)]
= p(1-p)/(2p - p2)
= (1-p)/(2-p)
(c) Here we have to prove that
P(X > n + m l X > m)
Here P(x > m) = 1 - P(x m) = 1 - [1 - (1-p)m] = (1-p)m
P(x > n + m l x > m) = [1 - (1-p)n+m]/ (1-p)m = (1-p)n
which is equals to P(X > n)
so we can say that geometric distribution has memoryless propoerty.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.