Please help explain these.. I am lost. Please explain step by step. The followin

Question

Please help explain these.. I am lost. Please explain step by step.

The following data segment starts at memory address 0x3700 (hexadecimal)
.data
printString BYTE "Do not add decimal to hex",0
someBytes WORD 29 DUP(0)
moreBytes BYTE 10, 20, 30, 40, 50, 60, 70, 80, 90
questionAddr DWORD ?
ignoreMe WORD ?

What is the hexadecimal address of questionAddr?

Answer is

0x375D

The following data segment starts at memory address 0x1600 (hexadecimal)
.data
printString BYTE "Assembly is fun",0
moreBytes BYTE 23 DUP(0)
dateIssued DWORD ?
dueDate DWORD ?
elapsedTime WORD ?

What is the hexadecimal address of dueDate?

Answer is  

0x162B

Explanation / Answer

public class Permutations { private Permutations() { } /** * N! permutation of the characters in the string (in order) */ public static String[] permutations(String stringToGeneratePermutationsFrom) { final int size = numberOfPermutations(stringToGeneratePermutationsFrom.length()); final String[] list = new String[size]; final char[] prefix = new char[0]; final char[] chars = stringToGeneratePermutationsFrom.toCharArray(); permutations(list, 0, prefix, chars, 0, chars.length); return list; } private static final int numberOfPermutations(int N) { // factorial int result = N; while (N > 1) result *= --N; return result; } private static final int permutations(String[] list, int index, char[] prefix, char[] remaining, int prefixLength, int remainingLength) { final int N = remainingLength-prefixLength; if (N == 0) { list[index]=new String(prefix); index++; } else { for (int i=0; i

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