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A.According to the International Mass Association survey, the amounts of money g

ID: 3361650 • Letter: A

Question

A.According to the International Mass Association survey, the amounts of money girls ages 13 to 15 spend monthly are Normally distributed with the average of $31.20 and the standard deviation of $8.27. If 85 girls in this age category are randomly selected, find the probability that their average monthly shopping expense is over $32.

Based on data from Consumer Reports, replacement times of TVs is on average 3.4 years with the standard deviation of 1.2 years. Answer the following questions.

B.A random sample of 41 TVs is selected. Find the probability that their average replacement time is between 3 and 4 years.

C.In case a random sample of 29 TVs was chosen, find the probability that their average replacement time exceeds 3.5 years.

The amounts of time required for room-service delivery at Radisson Hotels are Normally distributed with the average delivery time of 20 minutes. Answer the following questions.

D.A random sample of 21 deliveries was selected and their standard deviation was found to be 12.69 minutes. Find the probability that their average delivery time is longer than 27 minutes.

E.If a random sample of 12 deliveries was selected and their standard deviation was found to be 7.87 minutes, find the probability that their average delivery time is at most 25 minutes.

F. 70% of all art pieces auctioned by Sotheby’s in Japan are Japanese art. A random sample of 100 art pieces auctioned there is selected. Find the probability that at least 80% of these pieces are Japanese.

Explanation / Answer

A.According to the International Mass Association survey, the amounts of money girls ages 13 to 15 spend monthly are Normally distributed with the average of $31.20 and the standard deviation of $8.27. If 85 girls in this age category are randomly selected, find the probability that their average monthly shopping expense is over $32.

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Ans: Mean = 31.2

SD = 8.27

x = 32

z = (32 - 31.2)/8.27/85

z = 0.89

P(z > 0.89) = 0.1867

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