5. A least squa res regression line was computed to find the relationship betwee

Question

5. A least squa res regression line was computed to find the relationship between the distance a golf bal the ards) and the speed of the golf club (miles/hour) when it hits the ball. Obviously the faster speed the farther the ball will go. The following regression equation was o golfers whose club speed varies between 80 and 100 mi/hr btained based on averag Distance -22.5 + 2.83 x Club Speed yds The regression coefficient r=0.938 1 point) Do you think this is a model that can be used for further analysis? Mark one Y or N (1 pts) Would you consider it a (mark one): weak, moderate or a strong model? (1 pts) What statistical parameter are you using to base your conclusion? (1 pts) Predict how far my golf ball should go for a club speed of 90 mile/hour (I pts) Predict how far the golf ball goes for a club speed is 115 miles/hour (I pts) You look in your statistics book and conclude that your prediction for the 115 miles/hour may not be accurate. Explain why and how it affects the prediction you just made: (1 pts) The slope of the regression line is give both the numerator and the denominator with the appropria u (I pts) Explain what the numerical value of the slope means in the terms of this particular problem. (I pts) Give the numerical value AND the units of measurement for the vertical (y) intercept. Remember tha intercept is a POINT with both an x-coordinate and y-coordinate: (1 pts) Explain the significance (if any) of the intercept in terms of club speed and distance (1 pts) R2 for this regression was 88%. Explain what it means for the particulars of this problem

Explanation / Answer

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a) Yes, this model can be used for further analysis

b) Strong as r = 0.938

c) We are using r, correlation coefficient or we can also use r^2, coeefieicient of determination

d) Speed = 90

D = - 22.5 + 2.83 * 90

D = 232.2 yards

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