5. A conference is being held at a centre that has two different entrances. A re

Question

5. A conference is being held at a centre that has two different entrances. A registration desk is being set up at each entrance. Assume that each desk will have its own queue and will see an equal portion of the expected 125 total customers per hour arriving at the conference (assume Poisson arrivals), and that customers will not line jockey between registration desks since they are significant distances apart. If each registration desk can serve one customer at a time, and the average time to serve a customer is 0.75 minutes, then what will be the average time that a customer waits in a line (in minutes) before being able to register?

a.4.16 mins

b.2.67 mins

c.1.34 mins

d.1.17 mins

e.0.84 mins

Explanation / Answer

Answer:

Wq = average time a unit spends waiting in the queue = lambda / mu(mu-lambda)

here lambda = 80 customers per hour

and mu = 120 customers per

So Wq = 80 / 125 (125-80) = 80 / 125 x 35 = 1.17 mins

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