mine the point estimate of the population proportion, the margin of error, and t

Question

mine the point estimate of the population proportion, the margin of error, and the number of in the sample with specified characteristics,x, based on the following information:lower bound: 0.051, upper bound: 0.074, n- 1120. Find the point estimate, the margin of error, and x. 22) Listed below are the numbers of words spoken in a day by each member of six different couples randomly selected. Use = 0.05 significant level to test the claim that among couples males speak more words in a day than females. Husband 5638 wife 26429 13397 4697820 31553 25835 118667 213119624 5198 11661 t17572

Explanation / Answer

21)

2*ME = Upper bound - Lower Bound
ME = (0.074 - 0.051)/2 = 0.0115

consider z = 1.96 (95% CI)

ME = z * sqrt(p*(1-p)/n)
p*(1-p) = (ME/z)^2*n = (0.0115/1.96)^2*1120 = 0.0386

p - p2 - 0.0386 = 0

p = 0.9598 or p = 0.0402

x = 0.0402*1120 = 45.024 i.e 45

22)

p-value = 0.1509

As p-value is greater than the significance level of 0.05, we fail to reject the null hypothesis

There are not significant evidence to conclude that males speak more works than wifes.

Given Data Sample 1 Sample 2 Name Husbnd Wife mean 23961.8333 16683.3333 Sample size 6 6 Std. dev. 13586.15 8962.43

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