mined for each of your hypotheses and a diterent phenotype each of 2. Gene inter

Question

mined for each of your hypotheses and a diterent phenotype each of 2. Gene interaction without epistasis is often the result of a biochemical Consider the following pathways, where body color of a certain insect action of two enzymes, alpha and beta (a and ß, respectively). The combination of pigments yields blue color. species results from the the two creamgreen blue cream -> yellow A. What will the phenotype be for an insect homozygous for a nu D. What is your logic for the above? You may explain it in one gen alele off B. What will the phenotype be for an insect homozygous for a null C. What will the phen of both? phenotype be for an insect homozygous for null alleles Basic Content Knowledge (continued

Explanation / Answer

A) the phenotype for an organism is depends as well as generated on the basis of the genotype of the surround atmosphere. The given species of insect here having the allele of alpha will have the phenotype character of green colour because it have null allele.

B) for the case of insect having the homozygous of null allele if beta the character will be observed in it of yellow color. So the time phonotype observe in this case us that the insect will be of yellow color.

C) the phenotype for an insect which having the null allele of both will have the observed characteristics will have the combined form of phonotype here that is blue color character.

D) as we know that the phenotype is defined as the observed characteristics in a species or it is the observable traits of an organism such as it morpology and behavior. In the above cross breeding the character will be depends upon the allele and that will generate the phonotype here. In case of null allele the phonotype will be without combined and when it meet by cross breed it will form the blue color characteristics.

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