Dominique, Marco, Clarice, Roberto, and John work for a publishing company. The

Question

Dominique, Marco, Clarice, Roberto, and John work for a publishing company. The company wants to send two employees to a statistics conference. To be far, the company decides that the two individuals who get to attend will have their names draw from a hat. This is like obtaining a simple random sample of size 2. (a)Determine the sample space of the experiment. That is, list all possible simple random samples of size n = 2. (b) What is the probability that Clarice and Roberto attend the conference? (C) What is the probability that Robert attends the conference? (a) Choose the correct answer below. A. DM, DC, DR, DJ, MC, MR, MJ, CR, CJ, RJ, DD, MM, CC, RR, JJ B. DM, DC, DR, DJ MC, MR, MJ, CR, CJ, RJ, MD, CD, RD, JD, CM, RM, JM, RC, JC, JR C. DM, DC, DR, DJ D. DM, DC, DR, DJ, MC, MR, MJ, CR, CJ, RJ

Explanation / Answer

We will you the first letter of these 5 people only for our analysis. So D,M,C,R and J are five people outof which we have to select two people for conference

1) To Determine the same space you need to know all the combinations so there are 5C2 /2! (2! added because of repetition as we are indiffrenet between choice as DM or MD ) so there are total 10 possibilities .

Let's work them out. You just need to randomly pick 2 at a time from the sample without repetition.

So they are DM,DC,DR,DJ,MC,MR,MJ,CR,RJ,RJ these are total 10 possible outcomes . ans is (D)

2) probability that C and R attend the conference so it's =1(marked in underline above)/sample space = 1/10 =0.1 or 10%

3)What is the probability that R attends the conference

So let's see in howmany obesrvations R is there in the above space i.e 4 (in bold) and so prob = 4/sample space =4/10 =0.4 or 40%

I hope this has heped you understand the concept. Pls upvote if it has really helped you. God Luck

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