Dr. Henry believes that if he gives couples a measure of relationship satisfacti
ID: 3228425 • Letter: D
Question
Dr. Henry believes that if he gives couples a measure of relationship satisfaction (0-8) before he provide them couples therapy and then the same measure of relationship satisfaction (0-8) after therapy his patients will be less likely to divorce. He give his 41 clients the satisfaction measure then therapy for one month and gives the same 41 clients the satisfaction measure after therapy. (Total 18 pts)
Please answer the questions all the way through. Most people always skip the last two-three.*************
A. What are the independent and dependent variables and how are each scaled (1 pt each; Total 4 pts)?
Independent:________________________ Scaling:_____________________________
Dependent:__________________________ Scaling:_____________________________
B. What test should Dr. Henry use (2 pts)?__________________________________________________
C. Why that test (1 pts)?
D. What are the null and alternative hypotheses for that test (2 pts)?
E. What is the critical value for p=.05 (1 pts)? _________________________
G. If Dr. Henry calculates a test statistic of 2.11, should he (2 pts)? Retain H0 Reject H0
H. Interpret the findings (6 pts):
Explanation / Answer
Sol:
a)
Independent Variable: x1 (rating before therapy) on a scale of 0-8
Dependent Variable: x2 (rating after therapy) on a scale of 0-8
b)
Since the population standard deviation is not known, hence the doctor should use paired one tailed t test.
c)
Since the population standard deviation is not known, hence t test is used.
d)
Null Hypothesis (Ho):
µ2- µ1 = 0
Alternate Hypothesis (Ha):
µ2- µ1 < 0
e)
degrees of freedom = 41-1 = 40
alpha = 0.05
Critical value = -1.6839 (from t table)
f)
Since the test statistic is greater than Critical value, we fail to reject the null hypothesis.
g)
There is no sufficient evidence (at alpha = 0.05) to conclude that after Dr. Henry’s therapy, couples will be less likely to divorce
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