04: A coffee-dispensing machine is supposed to deliver 8 ounces of liquid into e

Question

04: A coffee-dispensing machine is supposed to deliver 8 ounces of liquid into each paper cup, but a consumer believes that the actual mean amount is less. The consumer obtained a sample of 49 cups of the dispensed liquid with average of 7.75 ounces.If the sample variance of the dispensed liquid per cup is 0.81 ounces, and ?-005, the p-value is approximately A. 0.06 B. 0.05 C. 0.025 D. 0.10 05: A coffee-dispensing machine is supposed to deliver 8 ounces of liquid into each paper cup but a consumer believes that the actual mean amount is less. T he consumer obtained a sample of 49 cups of the dispensed liquid with average of 7.75 ounces. If the sample variance of the dispensed liquid delivered per cup is 0.81 ounces, and ?-0.05, the appropriate decision is A. maintain status quo B. reduce the sample size C. fail to reject the 8-ounces claim D. reject the 8-ounces claim 6: The weight of a USB flash drive is 30 grams and is normally distributed. Periodically quality control inspectors at Dallas Flash Drives randomly select a sample of 17 USB flash drives. If the mean weight of the USB flash drives is too heavy or too light the machinery is shut down for adjustment; otherwise, the production process continues. The last sample showed a mean and standard deviation of 319 and 1.8 grams.respectively. Using-0.10, the appropriate decision is A. fail to reject the null hypothesis and do not shut down the process B. reject the null hypothesis and shut down the process C. do nothing D. fail to reject the null hypothesis and shut down the process

Explanation / Answer

Question 4

sample variance = 0.81

sample standard deviation = 0.9

Test statistic

Z = (7.75 - 8)/ [0.9/sqrt(49)] = -0.25/ [0.9/7] = -1.9444

P - value = Pr(Z < -1.9444) = 0.025

OPtion C is correct here.

Question 5

The approproiate decision is reject the 8 - ounces claim. Option D is correct.

Question 6

Sample mean = 31.9 gms

sample standard deviation = 1.8 gms

standard error of sample mean = 1.8/sqrt(17) = 0.4365

Here test statistic

t = (31.9 - 30)/ 0.4365 = 4.353

Here for alpha = 0.10 and two tailed test

tcritical = 1.746

so here we reject the null hypothesis and shut down the process.

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