030 (part 1 of 2) 10.0 points A proton in a cyclotron is moving with a speed of

Question

030 (part 1 of 2) 10.0 points A proton in a cyclotron is moving with a speed of 2.37 × 107 m/s in a circle of radius 0.648 m 1.67 × 10-27 kg is the mass of the pro- ton, and 1.60218 x 10-19 C is its fundamental charge. What is the magnitude of the force exerted on the proton by the magnetic field of the cyclotron? Answer in units of N 031 (part 2 of 2) 10.0 points What is the magnitude of the magnetic field required to keep it moving in this circle? Answer in units ofT 032 10.0 points A proton moving at 3.2 x 106 m/s through a magnetic field of 2.5 T experiences a magnetic force of magnitude 9.5 x 10-13 N What is the angle between the proton's velocity and the field? The charge on a proton is 1.60218 x 10-19 C and its mass is 1.67262 x 10-27 kg. Answer in units of

Explanation / Answer

Problem 30:

We know that, F = B q v = ( m v / q r ) * q v = m v^2 / r

= 1.67 x 10^-27 * (2.37 x 10^7)^2 / 0.648 = 1.45 x 10^-12 N

Problem 31:

B = m v / q r

= 1.67 x 10^-27 * 2.37x 10^7 / 1.60 x 10^-19 * 0.648 = 0.38 T

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