031 (part 4 of 4) 10.0 points Calculate the magnification for an object dis- tan

Question

031 (part 4 of 4) 10.0 points Calculate the magnification for an object dis- tance of 3.71 cm 032 (part 1 of 4) 10.0 points An object is placed 10 m before a convex lens with focal length 6.1 m. Another convex lens is placed 26.1 m behind the first lens with a focal length 5.1 m (see the figure below). Note: Make a ray diagram sketch in order to check your numerical answer. 6.1 m. 5.1 m 26.1 m V 10 m 0 5 10 15 20 25 30 35 40 45 At what distance is the first image from the first lens? Answer in units of m. 033 (part 2 of 4) 10.0 points What is the magnification of the first image? 034 (part 3 of 4) 10.0 points At what distance is the second image from the second lens? Answer in units of m. 035 (part 4 of 4) 10.0 points What is the magnification of the final image, when compared to the initial object?

Explanation / Answer

we will use thin lens formula here

f1 = 6.1 m ,

f2 = 5.1 m , p1 = 10 m , and

= 26.1 m

so 1/f=1/p+1/q

so 1/6.1-1/10=1/q1

p2=q1=15.64m--answer to part a

b) m1=-q1/p1

=-15.74/10

m=-1.574--answer to b

c)p2=L-q1

=26.1-15.74

=10.36m

q2=1/(1/f2-1/p2)

=1/(1/5.1)-(1/10.36)

q2=10.05m--answer to c

d)M=-q2/p2

=-10.05/10.36

=-0.97

mfinal=m1m2

=(-0.97)*(-1.574)

mfinal=1.52--answer to d

.

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