03144 03362 103438 103515 03593 03673 03754 Question 4 2.5 points Save Answer Us
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03144 03362 103438 103515 03593 03673 03754 Question 4 2.5 points Save Answer Use Table A of Cumulative Probabilities to answer the following question. Approximately 25% of all observations will lie below a z- 03836 04006 04182 04363 04551 04846 04947 2.5 points Save Answer 05155 05262 05370 05480 05592 Question 5 Using the information below, calculate the values for which 95% of values would fall in this normal distribution. Mean 62 Standard Deviation 3.7 95% of the values fall between . (Enter numeric values only. Do not enter parentheses or punctuation.) 05705 05821 2593 6057 06178 06301 06426 06552 06681 06811 6944 and 7215 7353 7493 7636 2.5 points Save Answer Using the information from question 5, calculate the values at +-3 standard deviations. -3 standard deviations: +3 standard deviations- Question 6Explanation / Answer
4. P(X<=c) = .25
So, Z value with cumulative area of 25% of all obs will be Z=.675
5. 95% of the value in the normal distribution will lie between :
Mean +/- Z*Stdev = 62+1.96*3.7 = 54.748 to 69.252
6. The value at +/- 3 standard deviations is :
-3 std = 62-3*3.7 = 50.9
+3 std = 62+3*3.7 = 73.1
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