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ID: 3169581 • Letter: H
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https://www.math d.com tudent playerHomework.aspx?homeworkid=4707628778 questionId-18 MAT 181 002 College Algebra Spring 2018 Homework: Hmw Section 1.4 Questions Score: 0 of 1 pt 1.4.99 shed:fals 14 of 14 (14 The distance to the surface of the water in a well can sometimes be found by dropping an object into the well and measuring the a sound is heard ift, is the time (in seconds) it takes tor the object to strike the water, then t, obeys the j. where s is the distance in feet) Solving for t, we have t,-5 /4. Let t2 be the time it takes for the sound el at a speed of approximately 1100 feet per second, the time to travel the distance s is t2-s/1100 Now t1·his the total time that elapses from the moment that the object is dropped to the moment that a sound is heard We have the equation Total elapsed time 012 : 4·1100 Enter your answer in the enswer box and then click Check Answer All parts showing Type here to search ithExplanation / Answer
Total time elapsed is = t (in seconds)
distance from the surface of the water in a well = s (in feet)
The formula of total time lapsed is = t = t1 + t2 = s1/2/4 + s/1100
It is given that t= 3 seconds;
s1/2/4 + s/1100 = 3;
Solving this we get s ~= 132.2 feet;
Thus, the total distance is about 132.2 feet from the surface of the water.
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