A trucking company conducted an ANOVA analysis comparing the mean mileage associ
ID: 3153787 • Letter: A
Question
A trucking company conducted an ANOVA analysis comparing the mean mileage associated with several different brands of tires. The ANOVA table is shown below.
a) How many brands of tires did the company compare?
b) What is the value of B in the ANOVA table? Give your answer to three decimal places.
c) What is the value of C in the ANOVA table? Give your answer to four decimal places.
d) Using a 0.05 level of significance, what is the critical point compared to the F statistic in order to make a conclusion? Give your answer to four decimal places.
e) Using a 0.05 level of significance, what conclusion should the company reach?
Reject the hypothesis that all brands have the same mean mileage.
Reject the hypothesis that one brand has a different mean mileage than the other brands.
Fail to reject the hypothesis that one brand has a different mean mileage than the other brands.
Fail to reject the hypothesis that all brands have the same mean mileage.
Explanation / Answer
a) How many brands of tires did the company compare?
it compared the 2+1 = 3 treatments
b) What is the value of B in the ANOVA table? Give your answer to three decimal places.
S.S.Total = S.S.E+ S.S.T = 10.289 + 17.2 = 27.489
c) What is the value of C in the ANOVA table? Give your answer to four decimal places.
M.S.E = S.S.Error/n-k = 17.2/19 = 0.9052
d) Using a 0.05 level of significance, what is the critical point compared to the F statistic in order to make a conclusion? Give your answer to four decimal places.
F Cal = MS Between / Ms Within = 5.682647
We got |F cal| = 5.682647 & |F Crit| =3.5218
MAKE DECISION
Hence Value of |F cal| > |F Crit|and Here We Reject Ho
e) Using a 0.05 level of significance, what conclusion should the company reach?
Reject the hypothesis that one brand has a different mean mileage than the other brands.
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