A truck is towing a car whose mass is one quarter that of the truck. The force e

Question

A truck is towing a car whose mass is one quarter that of the truck. The force exerted by the truck on the car is 6,000N. The force exerted by the car on the truck is: A. 1, 500N: B. 24,000N C. 3,000N D. 6,000N What must the separation be between a 5.2 kg particle and a 2.4 kg particle for their gravitational attraction to have a magnitude of 2.3 10^-12 N? Draw free body diagram of the bucket in each picture. Matthew pulls his little sister Sarah in a sled on an icy surface (no friction) with a force of 60 N at an angle of 60 degree upward from the horizontal. Find acceleration of the sled.

Explanation / Answer

1) The force exerted by the car on the truck is merely the equal and opposite reaction force to the truck's 6000 N. Like the tension in a cable.

by Newton's 3 rd law of motion the force on the car is D)

Whenever a first body exerts a force F on a second body, the second body exerts a force F on the first body. F and F are equal in magnitude and opposite in direction.

2) Gravitational attraction
F = G mm/r²
G = 6.67e-11 m³/kgs²
m and m are the masses of the two objects in kg
r is the distance in meters between their centers (center of mass)

2.3e-12 = (6.67e-11)(5.2)(2.4)/r²
r² = 361.92
r = 19 meters

4) The horizontal component of the force is 60 cos 60 = 30 N
Now you use F = ma
or a = F/m
but you need the mass of the sister and sled

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