Given the result of the previous problem, since E(x) is a continuous function, i

Question

Given the result of the previous problem, since E(x) is a continuous function, it makes sense for any real alpha to DEFINE E(x)alpha to be E(alpha x). Importantly then, if y > 0, then y = E(x) when x = L(y), and then we have y alpha = E(alpha L(y)). Using the definition that for any real number a and x > 0, that x alpha = E (alpha L(x)), show that the derivative of x alpha with respect to x is ax alpha - 1. Using the same definition with a > 0 and x a variable, compute the derivative of alpha x.

Explanation / Answer

x = E(xL()) = e^xln

Derivative of x = lne^xln =ln x

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.