Given the project information in the table below, determine the: Normal project
ID: 454244 • Letter: G
Question
Given the project information in the table below, determine the:
Normal project duration and critical path.
Normal project cost.
Critical path if the project is reduced by one day.
Revised project cost when the project duration is reduced by one day.
Activity
Predecessor(s)
Normal
Duration (Days)
Crash
Duration
(Days)
Normal
Cost
$
Crash
Cost
$
a
-
6
5
60
90
b
-
7
4
50
150
c
a
6
4*
100
160
d
a
7
7
30
30
e
b
5
4
70
85
f
c
9
7
40
120
g
d, e
7
5
50
230
Activity
Predecessor(s)
Normal
Duration (Days)
Crash
Duration
(Days)
Normal
Cost
$
Crash
Cost
$
a
-
6
5
60
90
b
-
7
4
50
150
c
a
6
4*
100
160
d
a
7
7
30
30
e
b
5
4
70
85
f
c
9
7
40
120
g
d, e
7
5
50
230
Explanation / Answer
The normal Project duration, with cost and critical path, is as follows:
The critical path is the longest path and its length is the duration of the project. Total normal cost is $400.
Acivities a, c, and g on the critical path are the critical activities and are the ones needs to be considered for crashing to reduce the duration of the project. Cost slope for "a" is (90-60)/(6-5)=30; for "c" is (160-100)/(6-4)=30; for "g" is (230-50)/(7-5)=90
Therefore Revised cost, for the project duration 20 days, after crashing either "a" or "c" by one day, is $430 (400+30).
Duration-days Cost-$ Activity Predecessor Normal Crash Normal Crash a - 6 5 60 90 b - 7 4 50 150 c a 6 4 100 160 d a 7 7 30 30 e b 5 4 70 85 f c 9 7 40 120 g d,e 7 5 50 230 Path b-e-g duration 20 days 400 Critical Path a-c-f duration 21 days Path a-d-g duration 20daysRelated Questions
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