5. 1/3 points ! Previous Answers DevoreStat9 9..011 My Notes Ask Your Teacher 0

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5. 1/3 points ! Previous Answers DevoreStat9 9..011 My Notes Ask Your Teacher 0 The level of lead in the blood was detemined for a sample of 152 male hazardous-waste workers age 20-30 and also for a sample of 86 female workers, resulting in a mean ± standard error of 5.8 ± 0.3 for the men and 3.8 0.2 for the women. Calculate an estimate of the difference between true average blood lead levels for male and female workers in a way that provides information about reliability and precision. (Use a 95% confidence interval. Round your answers to two decimal places.) I.L Interpret the interval We are 95% confident that the true average blood lead level for male workers is greater than that of female workers by an amount outside the confidence interval we are 95% confident that the true average blood lead level for male workers is less than that of female workers by an amount within the confidence interval We cannot draw a conclusion from the given information. we are 95% confident hat the true average blood ead level or male workers is greater than that of emale workers by an amount within the com de ce teva You may need to use the appropriate table in the Appendix of Tables to answer this question Submit Answer Save

Explanation / Answer

n1 = 152 , n2 = 86
x1 = 5.8 , x2 = 3.8

SE1 = 0.3 , SE2 = 0.2

SE1 = s1/sqrt(n1)
0.3 = s/sqrt(152)
s1 = 3.7

SE2 = s2/sqrt(n2)
0.2 = s/sqrt(86)
s2 = 1.9

z value at 95% =1.96

CI = (x1 - x2) +/-z *sqrt(s1^2/n1 + s2^2/n2)

= ( 5.8 - 3.8)+/- 1.96 * sqrt(3.7^2/152 + 1.9^2/86)
= (1.29,2.71)

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