5. + 1 points SerPSE99.P.031.MI My Notes A 10.0-g wad of sticky clay is hurled h

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5. + 1 points SerPSE99.P.031.MI My Notes A 10.0-g wad of sticky clay is hurled horizontally at a 110-g wooden block initially at rest on a horizontal surface. The clay sticks to the block. After impact, the block slides 7.50 m before coming to rest. If the coefficient of friction between block and surface is 0.650, what was the speed of the clay immediately before impact? m/s Need Help? .Readit. Master Master It My Notes 6. +-12 points SerPSE9 9.P.089.MI A 5.00-g bullet moving with an initial speed of vi 440 m/s is fired into and passes through a 1.00-kg block as shown in the figure below. The block, initially at rest on a frictionless, horizontal surface, is connected to a spring with force constant 850 N/m. The block moves d = 4.60 cm to the right after impact before being brought to rest by the spring (a) Find the speed at which the bullet emerges from the block. m/s (b) Find the amount of initial kinetic energy of the bullet that is converted into internal energy in bullet-block system during the collision. Need Help?RaMasterlt Master It

Explanation / Answer

5.

from the law of conservation of energy, we have:

KEf-KEi = -uNd

   0 - KEi = -uNd

-0.5(m1+m2)v2 = -u(m1+m2)gd

-0.5*v2  =-(0.65)(9.8)(7.5)

velocity of the block+clay after impact: v= 9.7749 m/s

from the law of conservation of momentum, we have

pi = pif

m1vi + 0 = (m1+m2)v

(0.01)vi + 0 = (0.01+0.11)(9.7749)

vi = 117.3 m/s

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