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ID: 3047645 • Letter: M

Question

MYour Chegg.com Reset Passwc xExam 1 ì Secure | https://asulearn.appstate.e > Quiz 1 Business Communic D vil-Papers e Chegg Study | Guided Solutio! × ATM Transaction Times Are NUX G how to take a full page screen Casey 2742799 :: Apps Teleco...- GENERAL INFO: c. d How to Treat Cuban. · * Cultural Information. cuba business com. r Cuba Communicati. . O The world Factbook as learn -Casey Yeargin Professor R. U. Kidding randomly surveyed 240 students at ASU and found that 150 of the students surveyed watch more than 10 hours of television weekly. Develop a 95% confidence interval to estimate the true proportion of students who watch more than 10 hours of television each week. The confidence interval is Not yet ECO2200350-15521201810 (SPRING 2018) Participants Badges Competencies Points out of 4.00 Flag question Select one: a. 0.533 to 0.717 b. 0.564 to 0.686 c. 0.552 to 0.698 d. 0.551 to 0.739 Grades General Question 14 Not yet Getting Started with Stats 2 Online Assume the grades on Stats Quiz 2 were normally distributed with a mean equal to 75 and a standard deviation equal to 5. Based on this, what is the probability that the mean grade in a sample of n = 25 will be between 72.5 and 77.5? Points out of 4.00 Fundamentals (Descriptive Statistics, Probability Distributions and Confidence Intervals) Select one: Y lag question a. 0.6937 b. 0.7786 C. 0.9876 d. 0.8897 Topic5 Dashboard Question 15 Not yet If you want to decrease the width of a confidence interval while maintaining the same level of confidence, you can Site home Points out of 4.00 Calendar Select one: a. decrease your sample size b. increase your significance level c. increase your sample size Flag question Private files My courses

Explanation / Answer

solution13:

p^=sample porportion of studentys who watch more tha 10 hrs

=x/n=150/240

=0.625

z crit for 95%=1.96

95% confidence interval for true population proprtion of students whow atch more than 10 hours is

p^-zcrit(sqrt(p^(1-p^/n),p^+zcrit(sqrt(p^(1-p^/n)

0.625-1.96*sqrt(0.625(1-0.625)/240),0.625+1.96*sqrt(0.625(1-0.625)/240)

=0.564,0.686

0.564<p<0.686

OPTION B FORM GIVEN CHOICES

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