Motorola used the normal distribution to determine the probability of defects an

Question

Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 9 ounces. The process standard deviation is 0.1, and the process control is set at plus or minus 1.75 standard deviations. Units with weights less than 8.825 or greater than 9.175 ounces will be classified as defects. What is the probability of a defect (to 4 decimals)? In a production run of 1000 parts, how many defects would be found (to 0 decimals)? Through process design improvements, the process standard deviation can be reduced to 0.06. Assume the process control remains the same, with weights less than 8.825 or greater than 9.175 ounces being classified as defects. What is the probability of a defect (rounded to 4 decimals; getting the exact answer, although not necessary, will require Excel)? In a production run of 1000 parts, how many defects would be found (to 0 decimals)? What is the advantage of reducing process variation?

Explanation / Answer

1)when std deviation =0.1

hence probability of defect =1-0.9199=0.0801

number of defects =1000*0.0801 =~80

2) when std deviation =0.06

hence probability of defect =1-0.9965=0.0035

number of defects =1000*0.0035 =~3

e advantage of reducing process variation that more number of parts will be with in tolerance level and therefore number of defects will get reduced

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