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For this discussion, you are asked to imagine the following situation and answer

ID: 3041074 • Letter: F

Question

For this discussion, you are asked to imagine the following situation and answer the questions Imagine you have to take a course that is taught by two different professors, say Dr. Johnson and Dr. Smith. You know that both professors use the same textbook, class materials, and assignments. The only difference is that each professor uses a different final exam. You know that the final exam scores for both Dr. Johnson and Dr Smith follow a normal distribution. Answer the following questions 1. What does it mean that the scores follow a "normal distribution"? How would you describe the "normal distribution" to someone who is unfamiliar with it? ading .ards 2. Would knowing that each professor's final exam distribution is normal convince you that both courses would be equally challenging and that it really doesn't matter which course you take? What additional data/information would ydu need to gather in order to make the best decision about which course to take? BUS Sp 01-011 irst chapt

Explanation / Answer

Answer to the question is as follows. Please write back in case of doubts:

1. By "normal distribution" , we mean a function that represents the distribution of many random variables as a symmetrical bell-shaped graph. Anything which has a bell curve distribution can be modelled by this "normal " function

2. yes, if we know that both' courses are normally distributed we would can come know that scoring different marks
can be equal in terms of challenging. Other info we must know are the parameters of normal distributions of both the exams
in order to compare scores between the exams

3.

A --> A>90
F --> F<=60

Now, in Johnson' final exam, mean = 76 and stdev = 7
Smith final exam, mean = 70 and stdev = 16

Lets calcualte the Z -value -->

Zjohnson = (90-76)/7 = 2
Zsmith = (90-70)/16 = 1.25

3. Based on the Zvalues, even if we score 2 deviations below mean in Dr Johnson' class we still can score more than 60, and therefore avoid a F . But same is not the in Smith' class, even a score 1 deviation below normal will score a F. So, taking Johnson' class is better than Smith'

4. Based on the above Zvalues:

Since Zsmith is 1.25 meaning he/she has to score just 1.25 deviation above mean to get an A,it makes sense to take Dr. Smith' course than 2 for Johnson'

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