The position function of an object moving along a straight line is given bys = f

Question

The position function of an object moving along a straight line is given bys = f(t).The average velocity of the object over the time interval [a, b] is the average rate of change of f over [a, b]; its (instantaneous) velocity at t = a is the rate of change of f at a.

A ball is thrown straight up with an initial velocity of 96 ft/sec, so that its height (in feet) after t sec is given by s = f(t) = 96t ? 16t2.
(a) What is the average velocity of the ball over the following time intervals [2,3] [2,2.5] [2,2.1] ?

Explanation / Answer

1)16m/s b)24m/s c)30.4 m/s

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