A hose and nozzle discharge a horizontal water jet against a nearby vertical pla

Question

A hose and nozzle discharge a horizontal water jet against a nearby vertical plate, as shown in the figure. The flow rate of water is 0.025 m3/s, and the diameter of the nozzle tip is 30 mm. Find the horizontal force that is necessary to hold the plate in place.

The answer should be 883 N to the left.

A hose and nozzle discharge a horizontal water jet against a nearby vertical plate, as shown in the figure. The flow rate of water is 0.025 m3/s, and the diameter of the nozzle tip is 30 mm. Find the horizontal force that is necessary to hold the plate in place. The answer should be 883 N to the left.

Explanation / Answer

Force acting on the plate = change in moment of water/ time

          change in moment/time=m*(Vfinal-Vinitial)/(time)

                                              =p*Q*(Vfinal-Vinitial)

                             in this case final velocity of the water in the direction of velocity of water is zero

                                               = p*Q*(Vinitial)

                                                =p*Q*(Q/(area))

                                               = 1000*0.025*0.025/(3.14*0.015^2)

The force acting on the plate =884N.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.