At 9.00 a.m. train T left a train station and 2 hours later train Sleft the same

Question

At 9.00 a.m. train T left a train station and 2 hours later train Sleft the same station on a parallel track. If train T averaged 60 km per hour and train S averaged 75 km per houruntill S overtook T , at what time did S overtake T?
Ans : 7 p.m.

I actually figure our the following solution.
Some one post the solution , but it's still not clear to me.i think the question actually says, the time needed S to overtakeT.

   60 ( t + 2) = 75 t
        t= 8
That mean's after 8 hours later S ovetakes train T
i don't understand how the answer is 7 p.m.
i appreciate anyone explain to me.

Explanation / Answer

the equation is given or you figured it out?

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