#1. Two groups of students took the same 100-point exam. Their scores have been
ID: 2923569 • Letter: #
Question
#1. Two groups of students took the same 100-point exam. Their scores have been organized into the back to back stem and leaf plot given below: | Group | | | Group 6 3 2 6 03 6 568 44444432200 7 0144 822 00 130017 735325 88888755 7 555556666788899 Hl 4432221000 8 000001111222233444 7666666555 8 5566666666666677888888899 422 9 000000000133 9 56 a) What is the third quartile for Group 12 (b) What isthe five number summary for Group ? (c) Does the core Jf60tn Crodp meet the rule ofthumb for outliers? ustify your answer.Explanation / Answer
a) there are n=44 elements in group I ; for which third quartile =3*(n+1)/4th value =3*45/4 =33.75 th value
and as 33 rd and 34th value is 85 ; therefore 3rd quartile =85
b)
for group 1;
values are
minimum =41
1st quartile Q1=(n+1)/4 th value =(82+1)/4 th value =20.75 th value=77.75
median =(n+!)/2 th value =41.5 th value =84
3rd quartile Q3=3*(n+1)/4 th value =3*(82+1)/4 th value =62.25 th value =88
maximum =96
hence 5 number summary is 41 ; 77.75 ; 84 ; 88 ; 96
c)here lower fence =Q1-1.5(Q3-Q1) =77.75-1.5*(88-77.75)=62.375
as score of 60 is below lower fence ; therefore it is outlier.
please revert for any clarification required
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.