A sewage treatment plant influent is estimated to have a typical BOD5 value of 3

Question

A sewage treatment plant influent is estimated to have a typical BOD5 value of 325 mg/L. What efficiency must the treatment plant have in order to meet the NPDES BOD5 requirement of less than 30 mg/L? Note: Your calculate efficiency must be entered with a unit of %. Again, note that the computer will give you an auto generated values for initial BOD5 (x). Every student will have a different values of BOD. Use the basic equation, solve your problem here and substitute the value given by the computer.

Explanation / Answer

BOD to be removed in order to meet the NPDES BOD5 requirement of 30 mg/L = 325 mg/L - 30 mg/L = 295 mg/L

BOD to be removed in order to meet the NPDES BOD5 requirement of less than 30 mg/L = more than 295 mg/L

Efficiency must the treatment plant have in order to meet

the NPDES BOD5 requirementof less than 30 mg/L = more than 295/325 *100 = more than 90.77 %

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