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A set of n = 5 pairs of x and Y values has ss_x = 10 ss = 40 and SP = 10. For th

ID: 3230113 • Letter: A

Question

A set of n = 5 pairs of x and Y values has ss_x = 10 ss = 40 and SP = 10. For these data, the Pearson a) r = 10/20 = 0.50 b)r = 10/400 0 = 025 c) r = 10/20 0 = 707 d) r = 40/100 = 0 40 Which of the following sets of correlations correctly shows the highest to lowest degree of relationship? a) 0.91, + 0 83, + 0.10. -0.03 b) -0.91, + 0 83, -0.03, -0.10 c) +0 83. +0.10, -0.91, -0, 03 d) +0.83, +0.10, 0.03, -0.91 The Pearson and the Spearman correlations are both computed for the same set of data If the Pearson correction is r = + 1.00, then what can you conclude about the Spearman correlation? a) It will be positive. b) It will have a value of 1.00 c) It will be positive and have a value of 1 00 d) There is no predictable relationship between the Pearson and the Spearman correlations. If the following scores are converted to ranks, what values should be assigned to the two individuals who started with scores of X = 5? Scores: 2, 3, 5, 5, 7, 10, 18 a) one receives a rank of 3 and the other gets a rank of 4 b) both should receive a rank of 3 c) both should receive a rank of 3.5 d) both should receive a rank of 4 Under what circumstances should the Spearman correlation be used? a) The researchers primary interest is the linearity of the relationship. b) The original data are measured on an ordinal scale of measurement c) The Pearson is too difficult to compute. d) All of the other options are appropriate circumstances for the Spearman correlation.

Explanation / Answer

14)

Here, we can calculate r with the help of the below formula:-

r^2=(SP)^2/(SSx)(SSy)=(10)^2/(10)(40)=100/400=0.25

r^2=0.25

Therefore, r=0.5

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