A diverging lens has a focal length of magnitude 24.6 cm. Locate the images for

Question

A diverging lens has a focal length of magnitude 24.6 cm. Locate the images for each of the following object distances. 49.2 cm distance location 24.6 cm distance location 12.3 cm distance location Is the image for the object at distance 49.2 real or virtual? real virtual Is the image for the object at distance 24.6 real or virtual? real virtual Is the image for the object at distance 12.3 real or virtual? real virtual Is the image for the object at distance 49.2 upright or inverted? upright inverted Is the image for the object at distance 24.6 upright or inverted? upright inverted Is the image for the object at distance 12.3 upright or inverted? upright inverted Find the magnification for the object at distance 49.2 cm. Find the magnification for the object at distance 24.6 cm. Find the magnification for the object at distance 12.3 cm.

Explanation / Answer

1/p + 1/q = 1/f, M = -q/p

a) p = 49.2 cm

1/49.2 + 1/q = 1/-24.6

q = -16.4 cm

M = 16.4 / 49.2 = 0.333

The object distance is negative, so virtual

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b) p = 24.6 cm

1/24.6 + 1/q = 1/-24.6

q = -12.3 cm

M = 12.3 / 24.6 = 0.5

The object distance is negative, so virtual

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c) p = 12.3 cm

1/12.3 + 1/q = 1/-24.6

q = -8.2 cm

M = 16.4 / 49.2 = 0.666

The object distance is negative, so virtual

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