A diver running 2.0 m/s dives out horizontally from the edge of a vertical cliff

Question

A diver running 2.0 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below.

A) How tall was the cliff in meters (please express answer with 2 significant figures)

B) How far from the base was the diver when they hit the water, in meters? (please express in 2 sig figs)

Thank you

Part A A diver running 2.0 m/s dives out horizontally from the edge of a vertical cliff and 2.6 s later reaches the water below. How high was the cliff? Express your answer using two significant figures Submit My Answers Give Up Part B How far from its base did the diver hit the water? Express your answer using two significant figures. d= Submit My Answers Give Up

Explanation / Answer

Part A

H = Vy(T) + ½ gT2

where

H = height of the cliff, Vy = vertical component of the initial velocity = 0

T = time, g = acceleration due to gravity = 9.81 m/s2

H = 0 + ½*9.81*2.62

H = 33.1575 m

H = 33 m (answer with 2 significant figures)

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Part B

d = Vx(T)

where,

Vx = horizontal velocity component, T = time

d = 2*2.6

d = 5.2 m (answer with 2 significant figures)

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