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A 2500n force pulls an object at along a frictionless surface at 0.25m/s2 . A) w

ID: 2308863 • Letter: A

Question

A 2500n force pulls an object at along a frictionless surface at 0.25m/s2 . A) what is the mass of the object? The object then a reaches a surface with friction,and the acceleration with friction is 0.15m/s2. B) what is the coefficient of kinetic friction? A 2500n force pulls an object at along a frictionless surface at 0.25m/s2 . A) what is the mass of the object? The object then a reaches a surface with friction,and the acceleration with friction is 0.15m/s2. B) what is the coefficient of kinetic friction? B) what is the coefficient of kinetic friction?

Explanation / Answer

a)

F = m*a

So, m = F/a

= 2500/0.25

= 10000 kg

b)

F - u*mg = m*a

So, 2500 - u*10000*9.8 = 10000*0.15

So, u = 0.01 <---- coefficient of kinetic friction

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