A 25.5g Al block is warmed to 65.4 degrees C and plunged into aninsulated beaker

Question

A 25.5g Al block is warmed to 65.4 degrees C and plunged into aninsulated beaker containing 55.2g water initially @22.2 degrees C.The aluminum and water are allowed to come to thermal equilibrium.Assuming that no heat is lost, what is the final tem of thealuminum and water? please tell me how to do this one. The answerisn't as important as setting up the problem! thanx. A 25.5g Al block is warmed to 65.4 degrees C and plunged into aninsulated beaker containing 55.2g water initially @22.2 degrees C.The aluminum and water are allowed to come to thermal equilibrium.Assuming that no heat is lost, what is the final tem of thealuminum and water? please tell me how to do this one. The answerisn't as important as setting up the problem! thanx.

Explanation / Answer

I don't have the specific heat for Al but I looked it up,so check to be sure it is correct with the one you have before yougive me a bad rating. -(25.5g)(0.89J/gC)(Tfinal-65.4C)=(55.2gH20)(4.184J/gC)(Tfinal-22.2C) There is a negative in front of Al because it is LOSINGheat. Solve for Tfinal. Tfinal=26.06C (check my math I did it fast) Thatis how the problem is set up.

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