A converging lens with a focal length of 6.60cmforms an image of a 3.40mm -tall

Question

A converging lens with a focal length of 6.60cmforms an image of a 3.40mm -tall real object that is to the left of the lens. The image is 1.40cm tall and erect.

Part A

Where are the object and image located?

Enter your answer as two numbers separated with a comma.

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A converging lens with a focal length of 6.60cmforms an image of a 3.40mm -tall real object that is to the left of the lens. The image is 1.40cm tall and erect.

Part A

Where are the object and image located?

Enter your answer as two numbers separated with a comma.

SubmitMy AnswersGive Up

Explanation / Answer

apply -1/f = 1/u +1/v

magnification m = -v/u = -(-1.4/3.4) = 0.4117

v = 0.4117u

so apply f = uv(u+v)

f = u * 0.4117 u/(1.4117u)

f = 0.4117u/1.4117

u = 1.4117 *6.6/0.4117

u = 22.63 cm

v = 0.4117*22.63

v = 9.3177 cm

so s.s' = 22.63cm, 9.31 cm

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