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A converging lens has a focal length of 15.0 c m . For each of two objects locat

ID: 2141526 • Letter: A

Question

A converging lens has a focal length of 15.0cm . For each of two objects located to the left of the lens, one at a distance of s1 = 21.0cm  and the other at a distance of s2 = 8.00cm  

a) determine the image position

     s1=_____cm

     s2=_____cm

b) determine the magnification

     m1=______

     m2=______


c)


d)


Both images are real. The image of the first object is real and the image of the second object is virtual. The image of the first object is virtual and the image of the second object is real. Both images are virtual.

Explanation / Answer

for converging length focal length is positive....


(1/s1)+(1/s1')=(1/f)....

(1/s1')=(1/f)-(1/s1)======>

s1'=s1*f/(s1-f)=52.5 cm on the opposite side of the object


for second object

s2'=s2*f/(s2-f)=-17.42 cm on the same side of the object


B) magnification m1=-s1'/s1=-2.5

m2=-s2'/s2=2.1



C)The image of the first object is real and the image of the second object is virtual


D)The image of the first object is inverted and the image of the second object is erect.

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