A block of mass \"m1\" is placed on an inclined plane with angle \"theta\" and i

Question

A block of mass "m1" is placed on an inclined plane with angle "theta" and is connected to a second hanging block of mass "m2" by a chord passing over a pulley . The coeffectient of kinetic friction is "mu k". Thr sytem is released from rest with block m2 dropping a distance h. Given [m1, theta, h, m2, mu k] Determine:

a)The work due to each of the forces on block 1 in moving h. (mg, N, Ff, T)

b)The work due toeach of the forces on block 2 in moving the distance h

c)The total work on the sytems and the speed of the blocks.

Please show work and explain

Explanation / Answer

a) Work done by mg is = m1*g*h*sin(theta)

Work done by T is = T*h

Work done by Ff is = - (mu k) * N* h

b) Work done by mg is = m2*gh

Work done by T is = -T*h

c) m1*g*h*sin(theta) - (mu k) * N* h+ m2*gh = 1/2 (m1 + m2)v^2 = Total Work = Change in K.E.

m1*g*h*sin(theta) - (mu k) * m1*g*cos(theta)* h + m2*gh = 1/2 (m1 + m2)v^2

v = ( 2* (m1gh (sin(theta) - (mu k) *cos(theta)) + m2*gh) / (m1+m2) )^0.5

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