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A particle rotates counterclockwise in a circle of radius 5-8 m with a constant angular speed of 14 rad/s. At. t = 0, the particle has an x coordinate of 0.98 m and y > 0. Figure: Not drawn to scale. Determine the x coordinate of the particle at t = 2.98 s. Answer in units of m 002 (part 2 of 3) 10.0 points Find the x component of the particle's velocity at t = 2.98 s.Answer in units of m/s 003 (part 3 of 3) 10.0 points Find the x component of the particle's acceleration at t = 2.98 s. Answer in units of m/s2

Explanation / Answer

1.The particle has moves 14 x2.98=41.72 rads in the time given.

The initial angle it has can be found out by cos theta=0.98/5.8,theta=1.4 rads.

After moving 41.72 rad counterclockwise,we have 1.4 +41.72 rads=43.12 rads= 5.42 rads=2.27 rads (in the fourth quadrant).=-49.45 deg.Hence the x coordinate is=r cos theta=3.77m

x component of the velocity at 2.98s=14x 5.8 x sin theta=61.69m/s

Since the angular velocity is constant,the only acceleration is the centripetal acceleration= v^2/r=1136.8m/s^2

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