-Magnesium reacts with sulfuric acid according to the following equation. How ma
ID: 1019653 • Letter: #
Question
-Magnesium reacts with sulfuric acid according to the following equation. How many liters of hydrogen gas can be made from 65.5 g of magnesium at STP?
Mg(s) + H2SO4(aq) MgSO4(aq) + H2(g)
-In the reaction of silver nitrate with sodium chloride, how many grams of silver chloride will be produced from 100. g of silver nitrate when it is mixed with an excess of sodium chloride? The equation for the reaction is below.
AgNO3(aq)+ NaCl(aq) AgCl(s) + NaNO3(aq)
-How many grams of water are produced from the reaction of 1.26 mol of oxygen according to this equation?
2H2(g) + O2(g) 2H2O(g)
-If 40.0 g of acetylene is allowed to react with 40.0 g of oxygen , how many grams of CO2 are formed?
2C2H2(g)+ 5O2(g) 4CO2(g) + 2H2O(g)
acetylene
-For the reaction of carbon dioxide to form carbon monoxide and oxygen, H is + 570 kJ. This reaction is
2CO2 (g) 2CO (g) + O2(g), H= + 570 kJ
-Magnesium sulfate reacts with barium chloride according to the following balanced equation. If 1.20 g of magnesium sulfate is allowed to react with 1.00 g of barium chloride in a water solution, what is the limiting reagent?
MgSO4(aq) + BaCl2(aq) BaSO4(s) + MgCl2(aq)
-The first step in the production of nitric acid is the formation of nitric oxide, NO, according to the following balanced equation.
4NH3(g)+ 5O2(g) 4NO(g) + 6H2O(g), H = -906 kJ
How many kJ are given off by the conversion of 34.0 g of ammonia?
Explanation / Answer
Mg(s) + H2SO4(aq) MgSO4(aq) + H2(g)
No of mol of Mg = 65.5/24 = 2.73 mol
1 mol Mg = 1 mol H2
No of mol of H2 produced = 2.73 mol
volume of H2 = 2.73*0.0821*273.17/1 = 61.22 L
AgNO3(aq)+ NaCl(aq) AgCl(s) + NaNO3(aq)
1 mol AgNO3 = 1 molAgCl
no of mol of AgNO3 = 100/169.87 = 0.6 mol
mass of AgCL Precipitated = 0.6*143.32 = 86 grams
2H2(g) + O2(g) 2H2O(g)
1 mol O2 = 2 mol H2O
mass of water produced = 1.26*2*18 = 45.36 grams
2C2H2(g)+ 5O2(g) 4CO2(g) + 2H2O(g)
No of mol of C2H2 = 40/26 = 1.54 mol
No of mol of o2 = 40/32 = 1.25 mol
limiting reactant = O2
mass of co2 produced = 1.25*(4/5)*44 = 44 grams
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