A resistor, R 1 , is connected to an ideal battery (no internal resistance) and

Question

A resistor, R1, is connected to an ideal battery (no internal resistance) and a current I1 = 0.39 A flows through the circuit.

The first resistor, R1, is then removed from the circuit and a differnt resistor, R2, is placed in the circuit in place of R1. The new resistor has a resistance R2 = 0.3 R1. A new current I2 flows.

What is the new current, I2?

Give your answer in A to three significant figures. Do not include units in your answer.

A resistor, R1, is connected to an ideal battery (no internal resistance) and a current I1 = 0. 39 A flows through the circuit. The first resistor, R1, is then removed from the circuit and a different resistor, R2, is placed in the circuit in place of R1. The new resistor has a resistance R2 = 0. 3 R1. A new current I2 flows. What is the new current, I2? Give your answer in A to three significant figures. Do not include units in your answer.

Explanation / Answer

V = IR

V = 0.39*R1

when secod connected ,

V = I2*R2

0.39*R1 = I2*(0.3*R1)

so I2 = 0.39/0.3

I2 = 1.3 amp

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